Physics / Torsion Pendulum & Shear Modulus
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EXPERIMENT 38 · PHYSICS LABORATORY

Torsion Pendulum & Shear Modulus lab report

A worked torsion pendulum & shear modulus lab report with simulated observation tables, graph, calculations, uncertainty and results.

WORKED EXAMPLE · SIMULATED OBSERVATIONS

A complete example report.

Simulated demonstration data.

This report shows the method and arithmetic. It is not evidence of a physical experiment. Replace its observations with your own measurements when preparing a real lab report.

Student: __________________Student ID: __________________Course: __________________Date: __________________Partner: __________________Instructor: __________________

1. Title and aim

Torsion Pendulum: Shear Modulus of a Wire and Rotational Harmonic Dynamics. Determine the shear modulus (modulus of rigidity) η of a steel suspension wire and investigate rotational harmonic oscillations by measuring the period of a torsion pendulum as a function of wire length.

2. Abstract

Five observations were generated from the ideal teaching model over the settings listed below. A straight-line fit gave an estimate of Shear modulus (modulus of rigidity) η of 78.50 GPa, differing by 0.003% from the model value. The reported scatter comes from scale rounding and any stated model approximation, not measured laboratory noise.

3. Apparatus and fixed settings

4. Theory and graph choice

The torsion pendulum is one of the most powerful and historically significant instruments in experimental physics, celebrated from Charles-Augustin de Coulomb’s discovery of electrostatics and Henry Cavendish’s weighing of the Earth to modern atomic force microscopy and micro-gyroscopes. When a horizontal cylindrical disc of moment of inertia I is suspended by a vertical wire of length L and radius r, twisting the disc through an angle θ creates a non-uniform shearing strain throughout the cross-section of the wire. In accordance with Hooke’s law in shear, the wire generates an elastic restoring torque τ = −κ θ, where κ = (π η r⁴) / (2 L) is the torsional rigidity of the wire and η is the shear modulus (modulus of rigidity) of the material. By Newton’s rotational second law I (d²θ/dt²) = −κ θ, the disc executes rotational simple harmonic motion with period T = 2π √(I / κ). Squaring this expression yields T² = [8π I / (η r⁴)] · L, establishing a strictly linear relationship between the square of the oscillation period T² and the active length L of the wire. By timing torsional vibrations across multiple wire lengths, ordinary least squares regression yields the slope S = 8π I / (η r⁴), from which the shear modulus η is determined with high precision. This experiment elucidates the fundamental connection between microscopic atomic bond resistance to tangential shear and macroscopic rotational elasticity.

T² = \left(\frac{8\pi I}{\eta r^4}\right) L

The calculation fits y = mx + b in SI units. The graph may display scaled axes for readability; those display factors are removed before calculating the physical result. The gradient has units s² m⁻¹.

5. Method

  1. Using the digital micrometer screw gauge, determine the zero error, then measure the diameter d of the steel wire at ten distinct locations along its length and at mutually perpendicular orientations. Compute the mean diameter d and radius r = d / 2.
  2. Insert the wire into the upper wall chuck and lower disc collet. Adjust the active free length L between the clamp jaws to the first test station (e.g. L = 40.0 cm) and tighten both collets firmly so no slipping occurs during rotation.
  3. Gently twist the inertia disc in a horizontal plane through an initial angle of approximately 10° to 15°, ensuring that no lateral swinging, pendular wobble, or vertical bounce modes are excited, and release it smoothly from rest.
  4. Discard the first complete oscillation cycle to eliminate release transients. As the radial index pointer on the disc crosses the stationary equilibrium fiducial mark moving in a chosen direction, start the digital chronometer and time 20 complete oscillations to obtain t₂₀.
  5. Repeat the timing procedure across five distinct wire lengths L = 40.0 cm, 50.0 cm, 60.0 cm, 70.0 cm, and 80.0 cm. For each length, record duplicate trials to verify repeatability and compute the mean period T = t₂₀ / 20.
  6. Construct a plot of period squared T² on the vertical axis against active wire length L on the horizontal axis. Compute the slope S = d(T²)/dL using ordinary least squares regression, and calculate the shear modulus η = (8π I) / (S · r⁴).

6. Observations and calculation table

All observations use fixed model settings. Values are rounded only at the instrument reading stage; further calculations use full precision. Repeated physical trials are not claimed.

Table 1. Five simulated measurements; x and y are in SI units.
No.Suspension Wire Length L (cm)Time for 20 Oscillations t₂₀ (s)x (SI)y (SI)Fitted y (SI)Residual (SI)
140.062.870.400009.881599.88165-5.3150e-05
250.070.290.5000012.3517112.35196-2.5195e-04
360.077.000.6000014.8225014.822282.2100e-04
470.083.170.7000017.2931217.292605.2645e-04
580.088.910.8000019.7624719.76291-4.4235e-04

Download the sample observations (CSV) ↓

7. Worked calculation for one observation

Suspension wire length L = 40.0 cm = 0.4000 m; observed time for 20 oscillations t₂₀ = 62.87 s; period T = 3.1435 s; period squared T² = 9.88159 s². Single-trial shear modulus estimate η = (8π I L) / (T² · r⁴) = (8π × 0.0100 × 0.4000) / (9.88159 × (0.000600)⁴) = 78.50 GPa. Linear regression of T² against L across all length stations yields the reported slope and shear modulus.

8. Graph, gradient and final calculation

8.890.3611.860.4814.820.6017.790.7220.750.84Wire length L (m)Period squared T² (s²)

Dots show the sample observations. The line is the ordinary least-squares fit.

x̄ = 0.60000; ȳ = 14.82228
Σ(x − x̄)² = 0.10000
Σ(x − x̄)(y − ȳ) = 2.47032
m = Σ(x − x̄)(y − ȳ) / Σ(x − x̄)² = 24.70316800
b = ȳ − mx̄ = 3.7820e-04
Slope S = 24.703168 s² m⁻¹; I = 0.0100 kg m²; r = 0.600 mm; Shear modulus η = 8π I / (S · r⁴) = 7.8502e+10 Pa (78.50 GPa); Intercept b = 3.7820e-04 s²

9. Uncertainty and comparison

Percentage difference = |estimate − model value| / |model value| × 100 = 0.0029%. Percentage difference is not experimental uncertainty.

For n = 5 observations, Σresidual² = 5.8797e-07; s² = Σresidual²/(n − 2). Gradient standard error = √[s²/Σ(x − x̄)²] = 0.00140. Intercept standard error = √[s²(1/n + x̄²/Σ(x − x̄)²)] = 8.6299e-04.

Propagating only the relevant fit coefficient gives a fit-only standard error of 0.00445 GPa. This is a one-standard-error quantity under the regression assumptions. Deterministic rounded model data do not supply a complete physical uncertainty budget.

Fourth-power error amplification in measuring wire radius r (dr/r ±0.17% producing ±0.68% uncertainty in η), active length measurement precision between clamp jaws (±0.5 mm), split-collet clamp compliance and microscopic end slipping, inertia disc mass calibration tolerance (±0.05 g) and machining radius tolerance (±0.05 mm), small parasitic pendulum swinging or wobble coupling, and acrylic shield draft suppression contribute experimental uncertainty. The OLS regression standard error reflects random scatter across length stations, but does not capture shared wire diameter calibration offsets.

10. Result and discussion

η = 78.50 GPa = 78.50 GPa
Model comparison value: 78.50 GPa

The observations follow the stated model relationship. Check whether the intercept and residual pattern suggest a systematic offset or a missing approximation. Agreement with the model does not independently verify its input constants.

11. Precautions and limitations

The teaching model assumes a perfectly elastic, homogeneous, isotropic circular wire with zero internal friction and negligible wire self-inertia. In a physical laboratory, small corrections for the moment of inertia of the wire (I_wire = (1/2) m_wire r²), slight non-circularity of the wire cross-section, and clamp end compliance introduce minute second-order adjustments. The torsion pendulum experiment provides an indispensable bridge between rotational mechanics and continuum elasticity theory. By evaluating the fourth-power dependence of torsional rigidity on wire radius (the r⁴ law), students appreciate how nanoscale interatomic shear resistance governs macroscopic rotational resonance, enabling precise determination of the modulus of rigidity η.

12. Conclusion

The worked example illustrates how to obtain Shear modulus (modulus of rigidity) η from measurements, graph variables and a fitted coefficient. The estimate is 78.50 GPa. A real experiment must additionally evaluate the apparatus-specific uncertainties and corrections described above.