Derive the van 't Hoff equation from fundamental thermodynamic principles and explain how it determines ΔH° and ΔS° without calorimetry.
The fundamental definition of Gibbs free energy gives ΔG° = −R T ln K_eq, which rearranges to ln K_eq = −ΔG° / (R T). Differentiating with respect to temperature at constant pressure: d(ln K_eq)/dT = −(1/R) · [ ∂(ΔG°/T) / ∂T ]_P. According to the Gibbs-Helmholtz equation, [ ∂(ΔG°/T) / ∂T ]_P = −ΔH° / T². Substituting this gives the differential van 't Hoff equation: d(ln K_eq)/dT = ΔH° / (R T²). Noting that d(1/T) = −(1/T²) dT, the derivative with respect to inverse temperature becomes: d(ln K_eq) / d(1/T) = −ΔH° / R. Assuming ΔH° is independent of temperature over a moderate span, integrating yields: ln K_eq = −(ΔH° / R) · (1/T) + C. Because ΔG° = ΔH° − T ΔS°, comparing ln K_eq = −ΔH°/(RT) + ΔS°/R reveals that the integration constant is C = ΔS° / R. Thus, a linear plot of ln K_eq versus (1/T) has slope m = −ΔH° / R and intercept b = ΔS° / R. This allows complete extraction of both enthalpy and entropy purely from equilibrium measurements.